What must be subtracted from 3a²-6ab - 3b2-1 to get 4a²- 7ab – 4b² +1 ?
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Answered by
0
it is an algebric expression so his answer is a^2 +ab+b2+1
Answered by
3
Answer:
a² - ab - b² + 2
Step-by-step explanation:
1. So in this sum u take the second term first and put the second term in brackets
4a²- 7ab - 4b² + 1 - (3a²-6ab - 3b²-1)
2. Then you open the brackets
4a²- 7ab - 4b² + 1 - 3a²+ 6ab + 3b²+ 1
3. now take the like terms
4a²- 3a²- 7ab + 6ab - 4b² + 3b² + 1 + 1
4. which is:
= a² - ab - b² + 2
Hope you got it :)
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