what number must be added to each of a term of the ratio 7:5,so that the ratio becomes 5:4
Answers
Answered by
9
so let the no. be added be x
so the according to question
(7 + x)/(5 + x) = 5/4
28 + 4x = 25 + 5x
x = 3
so if we add 3 to both terms we get the required answer
ie (7+3)/(5+3) = 10/8 = 5/4
so the according to question
(7 + x)/(5 + x) = 5/4
28 + 4x = 25 + 5x
x = 3
so if we add 3 to both terms we get the required answer
ie (7+3)/(5+3) = 10/8 = 5/4
Answered by
4
Let the number be x
(7+x)/(5+x)=5/4
then 28=4x=25+5x
⇒ x=3
The number is 3
(7+x)/(5+x)=5/4
then 28=4x=25+5x
⇒ x=3
The number is 3
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