what number should be added to each of the numbers 12 ,22, 42 and 72 so that the resulting numbers may be in proportion
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let the number to be added be X.
therefore:

cross multiply and create an equation. The following will be formed.

on solving it further you will get:

therefore the number will be 3.
therefore:
cross multiply and create an equation. The following will be formed.
on solving it further you will get:
therefore the number will be 3.
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