Question

What number should be subtracted from x^3+4x^2-7x+12 if it is to be perfectly divisible by x+3?

Answer 1

$\textbf{HEY MATE!}$

$x + 3 = 0 \: = > x = - 3 \\ \\ =( - 3 {)}^{3} + 4( - 3 {)}^{2} - 7( -3) + 12 - k = 0 \\ \\ = > - 27 + 36 + 21 + 12 = k \\ \\ k = 42$


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