Question

What percentage of 5 digut number whose sum of digut is 43, are divisible by 11?

Answer 1

Step-by-step explanation:

Let the five-digit numbers be represented by x1x2x3x4x5.

As the digits of these numbers should add up to 43, we have

x1+x2+x3+x4+x5=43(where 1≤xi≤9, xi∈N)

So, the number of such numbers is equal to the coefficient of x43 in (1−x101−x)5=15

As this is a listable amount of numbers so lets just list them

999979997999799979997999999988998899889988999998989898989899989988998989998