Question

what should be added to 9 whole 2 by 3 to get 19

Answer 1

Let the number which must be added=x
Therefore, according to question,
9whole2/3+x=19
=>29/3+x=19
=>x=19-29/3
=>x=57/3-29/3
=>x=28/3
28/3 is the required answer

Answer 2

Answer:

13 should be added to 9 whole 2 by 3 to get 19.

Step-by-step explanation:

Here we want find that what should be added to 9 whole 2 by 3 to get 19.

9 whole 2 by 3

$= 9 \frac{2}{3} = \frac{9 \times 2}{3} = 3 \times 2 = 6$

Let we should be add with 6 to get 19.

So,

$x + 6 = 19$

We are separating variable and constant part,

$x = 19 - 6 = 13$

So required value is 13.

This is a problem of Algebra.

Some important formulas of Algebra,

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

${a}^{2} - {b}^{2} = (a + b)(a - b)\\{a}^{2} + {b}^{2} = {(a + b)}^{2} - 2ab\\{a}^{2} + {b}^{2} = {(a - b)}^{2} + 2ab\\{a}^{3} - {b}^{3} = (a - b)( {a}^{2} + ab + {b}^{2} )\\{a}^{3} + {b}^{3} = (a + b)( {a}^{2} - ab + {b}^{2} )$