Math, asked by manshukapoor51, 6 months ago

What should be subtracted from 15x² - 6y + xy + 19 to obtain 3x' -1 2y + 4xy - 31?

Answers

Answered by sitanshusarangi
1

Answer:

12x² + 6y - 3xy + 50

Step-by-step explanation:

Let a should be subtracted from 15x² - 6y + xy + 19 to get 3x² -1 2y + 4xy - 31.

15x² - 6y + xy + 19 - a = 3x² -1 2y + 4xy - 31

=> a = (15x² - 6y + xy + 19) - (3x² -1 2y + 4xy - 31)

=> a = 15x² - 6y + xy + 19 - 3x² + 12y - 4xy + 31

=> a = 15x²-3x² + 12y-6y - 4xy+xy + 19+31

=> a = 12x² + 6y - 3xy + 50

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