Math, asked by kareenabhatia17, 4 months ago

what should be taken away from 3 x square minus 4 y² + 5XY + 22 - x square minus y² + 6XY+20?​

Answers

Answered by shivapandey68
2

Answer:

Let q should be subtracted.

Then according to question,

3x2−4y2+5xy+20−q=−x2−y2+6xy+20

⇒q=3x2−4y2+5xy+20−(−x2−y2+6xy+20)

⇒q=3x2−4y2+5xy+20+x2+y2−6xy−20

⇒q=3x2+x2−4y2+y2+5xy−6xy+20−20

⇒q=4x2−3y2−xy+0

Hence, 4x2−3y2−xy should be subtracted.

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