What volume of air containing 21percentof oxygen at NTP required to 1lit of so2to so3atNTP
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Explanation:
21% of oxygen by volume means for 1 L of air volume of oxygen will be 0.21L and as we know 1 mole of ideal gas occupy 22.4L volume at STP i.e. Standard temperature and pressure. It implies 0.21L of oxygen will have 0.21*(1/22.4) moles of oxygen i.e. 0.009375 moles of oxygen and that is your answer.
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