Question

what volume of oxygen at 18 degree Celsius and 750 mm pressure can be obtained from 10 g of potassium chlorate.​

Answer 1

Answer:

please mark me as brainliest

Explanation:

The reaction is as follows:

2 KClO3(s) → 3 O2(g) + 2 KCl(s)

Molar mass 122.55

so 245 gr will produce (ideally) 16x6= 64 gr Oxygen

so, 18 gr KClO3 will produce 64x18/245 = 4.7 gr O2

32 gr oxygen will have a volume of 22.4 liter at 20deg c (293 deg K) and 760 mm Hg.

4.7 gr will have a vol. of 22.4x4.7/32 = 3.29 at normal cond.

now to 18 deg and 750mm

3.29x(760/750)x(291/293)… now you get out your calculator and figure out the result.