Question

What volume of water should be added to 500mL of 2 N(f=0.98) Na2CO3 to make it exactly N/10?​

Answer 1

Answer:

9310ml

Explanation:

inital volume:5000ml

normality:2N

normalityfactor:0.98

final normality:0.1

Now,

N1*V1=N2*V2

2*500=0.1*V2

V2=10000 ml

Again,

Needed volume of water=10000-500=9500ml

Now,. Normality factor=actual wt./theoritical wt

0.98*9500=9310