What will be the energy shared in the spring at the instant when the 10 kg mass has acceleration 12 m/s2 if two masses 10 kg and 20 kg are connected by a massless spring. A force of 200 n acts a 20 kg mass?
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Consider masses A and B of mass 10kg and 20kg.
As per the question,
The acceleration of A is 12 m/s²
Thus Acceleration of 10kg mass =12m/s²
Force acting on A is ma
Force=ma
F=10x12=120N will act .
Force acting on B given as 200 N.
Since, both are connected by spring, so the net force acting on B = Force on B - Force on A
Net force on 20kg mass will be :
200N-120 N=80N
a=F/m
=80/20
=4m/s²
∴ The acceleration of 20kg mass is 4m/s²
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nice question
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