Chemistry, asked by jameyj8262, 10 months ago

What will be the equivalent weight of k2cr2o7 in acidic medium?

Answers

Answered by sohansnair1563717

1

Answer:49 grams

Explanation:

In acidic medium, K2Cr2O7 (Cr+6)..reduces to Cr+3

Change in oxidation state per mole of Cr=3

Net change in oxidation state of Cr =2×3=6

Therefore, n-factor for K2Cr2O7 in acidic medium is 6

Equivalent weight = (molecular weight)÷n-factor

=(78+104+112)÷6 =294÷6=49 grams

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