Question

What will be the height attained by a stone thrown upwards at a velocity of 8m/s.  ​

Answer 1

Answer

The height attained by the stone thrown vertically upwards at a velocity of 8m/s will be 3.265m.

Given,

Initial velocity of the stone (u) = 8m/s

To find,

Height attained by the stone

Solution

We know that,

1. acceleration due to gravity (g) = 9.8m/s^2

2. the final velocity (v) at the topmost point when an object is thrown up is zero

3. For motion under gravity, v^2 = u^2 + 2gh where v is the final velocity, u is the initial velocity, g is the acceleration due to gravity and h is the height attained.

Now let's put the values of u, v, g and h in the formula,

v^2 = u^2 + 2gh

0×0 = 8×8 + 2×(-9.8)×h

19.6h = 64

Thus, h = 3.265m

Hence, the height attained by the stone thrown vertically upwards at a velocity of 8m/s will be 3.265m.