Question

what will be the labour charges for digging a cuboidal pit 8 metre long 6 metre broad and 3 metre deep at the rate of Rs 20 per metre³​

Answer 1

Answer:

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Answer 2

$\large\underline{ \underline{ \sf \maltese{ \: Question:- }}}$

• what will be the labour charges for digging a cuboidal pit 8 metre long 6 metre broad and 3 metre deep at the rate of Rs 20 per metre³ ?

$\large\underline{ \underline{ \sf \maltese{ \: Diagram:- }}}$

$\setlength{\unitlength}{0.74 cm}\begin{picture}\thicklines\put(5.6,5.4){\bf A}\put(11.1,5.4){\bf B}\put(11.2,9){\bf C}\put(5.3,8.6){\bf D}\put(3.3,10.2){\bf E}\put(3.3,7){\bf F}\put(9.25,10.35){\bf H}\put(9.35,7.35){\bf G}\put(3.5,6.1){\sf 8\:cm}\put(7.7,6.3){\sf 6\:cm}\put(11.3,7.45){\sf 3\:cm}\put(6,6){\line(1,0){5}}\put(6,9){\line(1,0){5}}\put(11,9){\line(0,-1){3}}\put(6,6){\line(0,1){3}}\put(4,7.3){\line(1,0){5}}\put(4,10.3){\line(1,0){5}}\put(9,10.3){\line(0,-1){3}}\put(4,7.3){\line(0,1){3}}\put(6,6){\line(-3,2){2}}\put(6,9){\line(-3,2){2}}\put(11,9){\line(-3,2){2}}\put(11,6){\line(-3,2){2}}\end{picture}$

$\large\underline{ \underline{ \sf \maltese{ \: Given:- }}}$

• Length of the Cuboidal Pit = 8 metre
• Breadth of the Cuboidal Pit = 6 metre
• Height of the Cuboidal Pit = 3 metre
• Digging Charges = Rs, 20 per m³

$\large\underline{ \underline{ \sf \maltese{ \: </strong><strong>To </strong><strong>\</strong><strong>:</strong><strong> </strong><strong>Find</strong><strong>:- }}}$

• Charges of the Labour for Digging a Cuboidal Pit with the Given Dimensions.

$\large\underline{ \underline{ \sf \maltese{ \: </strong><strong>Solution</strong><strong>:- }}}$

$\begin{gathered}\begin{gathered}\begin{gathered}: \implies \underline\blue{ \boxed{\displaystyle \sf \bold\orange{\: Volume \: of \: the \: Pit \: = \: Length\: \times \: Breadth \: \times \: Height }} }\\ \\\end{gathered}\end{gathered}\end{gathered}$

$\qquad \quad {:} \longrightarrow \sf{\sf{Volume \: of \: the \: Pit \: = \: 8\: \times \: 6 \: \times \:3 }}$

$\qquad \quad {:} \longrightarrow \sf{\bf{Volume \: of \: the \: Pit \: = \: 144{m}^{3} }}$

$\qquad\quad {:} \longrightarrow \underline \red{\boxed{\sf{Volume \: of \: the \: Pit \: = \: 144{m}^{3} }}}$

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Since, Labour Charges are at the Rate of Rs,20 per m³.

$\underbrace\red{\boxed{ \sf \blue{ Total \: Labour \: Charges }}}$

$\qquad \quad {:} \longrightarrow \sf{\bf{Total \: Labour \: Charges \: = \: Volume \: of \: pit \: \times \: 20}}$

$\qquad \quad {:} \longrightarrow \sf{\sf{Total \: Labour \: Charges \: = \: 144 \: \times \: 20 }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{Total \: Labour \: Charges \: = \: 2880 }}$

$\qquad\quad {:} \longrightarrow \underline \red{\boxed{\sf{ Total \: Labour \: Charges \: = \: Rs,2880 }}}$

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$\begin{gathered}\begin{gathered}\qquad \therefore\: \sf{Total \: Labour \: Charges \: = \underline {\underline{ Rs, 2880}}}\\\end{gathered}\end{gathered}$

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More For Knowledge:-

$\begin{array}{|c|c|c|}\cline{1-3}\bf Shape&\bf Volume\ formula&\bf Surface\ area formula\\\cline{1-3}\sf Cube&\tt l^3}&\tt 6l^2\\\cline{1-3}\sf Cuboid&\tt lbh&\tt 2(lb+bh+lh)\\\cline{1-3}\sf Cylinder&\tt {\pi}r^2h&\tt 2\pi{r}(r+h)\\\cline{1-3}\sf Hollow\ cylinder&\tt \pi{h}(R^2-r^2)&\tt 2\pi{rh}+2\pi{Rh}+2\pi(R^2-r^2)\\\cline{1-3}\sf Cone&\tt 1/3\ \pi{r^2}h&\tt \pi{r}(r+s)\\\cline{1-3}\sf Sphere&\tt 4/3\ \pi{r}^3&\tt 4\pi{r}^2\\\cline{1-3}\sf Hemisphere&\tt 2/3\ \pi{r^3}&\tt 3\pi{r}^2\\\cline{1-3}\end{array}$

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