Question

What will be the number of real zeroes of the polynomial x2 + 1?

Answer 1

hey friend your answer is
p(x)=x²+1
put p(x)=0
x²+1=0
x²- (-√1)²=0
now open the Formula a²-b²
(a+b)(a-b)
x=1or -1

Answer 2

Answer:

There are no real zeroes of the above polynomial.

Step-by-step explanation:

Given the polynomial

$x^2+1$

we have to find the number of real zeroes of the polynomial.

To find the zeroes we have to put to polynomial equals to 0 and then find the value of x.

$x^2+1=0$

$x^2=-1$

$x=\pm\sqrt{-1}$

There are no real zeroes of the above polynomial.