Question

what will be the solution 40x+40x/x-4=50/6 ?​

Answer 1

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what will be the solution 40x+40x/x-4=50/6 ?

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$= > 40x + \frac{40x}{x - 4} = \frac{50}{6}$

$= > \frac{40x(x - 4) + 40x}{x - 4} = \frac{50}{6}$

$= > \frac{40 {x}^{2} - 160x + 40x }{x - 4} = \frac{50}{6}$

$= > \frac{40 {x}^{2} - 120x}{x - 4} = \frac{50}{6}$

$= > 240 {x}^{2} - 720x = 50x - 200$

$= > 240 {x}^{2} - 720x - 50x + 200 = 0$

$= > 240 {x}^{2} - 770x + 200 = 0$

=>taking 10 common from whole equation:-

$= > 24 {x}^{2} - 77x + 20 = 0$

Now,Here we use quadratic formula to find out the roots:-

Here,a=24;b=-77 & c=20

$= > x = \frac{ -b± \sqrt{ {b}^{2} - 4ac} }{2a}$

$= > x = \frac{77± \sqrt{5929 - 1920} }{40}$

$\bold{= > x = \frac{77± \sqrt{4009} }{40} }$

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