Question

what will be the solution of this that what will be the current drawn by electric bulb of 40 w when it connected to a series of 220v

Answer 1

power = current × potential difference
40 = current × 220
40/220 = current
or
current = 0.181 Ampere

Answer 2

$\displaystyle \text{It's given,}\\\text{Power = 40 W}\\\text{Voltage = 220 V}\\\text{Current = ?}\\\\\text{We know,}\\P = VI\\40=220\times I\\I = \frac{40}{220} \\I = \frac{2}{11} \text{ or 0.18}\\\\\bullet Current = 0.18 \text{ A}$