What will be the sum of adding all the possible three digit numbers formed by 7,2,5 using each of the digits only once
Answers
Answer:
3108
Step-by-step explanation:
possible 3 digit numbers
- 725
- 752
- 275
- 257
- 527
- 572
Their sum=> 725+752+275+257+527+572
= 3108
The sum of adding all the possible three digit numbers formed by 7 , 2 , 5 using each of the digits only once is 3108
Given :
The numbers 7 , 2 , 5
To find :
The sum of adding all the possible three digit numbers formed by 7 , 2 , 5 using each of the digits only once
Solution :
Step 1 of 2 :
Write down all possible three digit numbers
Here the given numbers are 7 , 2 , 5
Since we can use each of the digits only once
So total number of possible three digit numbers
= 3!
= 6
All possible three digit numbers are 725 , 752 , 275 , 257 , 527 , 572
Step 2 of 2 :
Calculate the sum
The sum of adding all the possible three digit numbers formed by 7 , 2 , 5 using each of the digits only once
= 725 + 752 + 275 + 257 + 527 + 572
= 3108
Shortcut method :
The sum of adding all the possible three digit numbers formed by a , b , c using each of the digits only once is 222 × (a + b + c)
∴ The sum of adding all the possible three digit numbers formed by 7 , 2 , 5 using each of the digits only once
= 222 × (7 + 2 + 5)
= 222 × 14
= 3108
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