Question

What will be the sum of adding all the possible three digit numbers formed by 7,2,5 using each of the digits only once​

Answer 1

Answer:

3108

Step-by-step explanation:

possible 3 digit numbers

• 725
• 752
• 275
• 257
• 527
• 572

Their sum=> 725+752+275+257+527+572

= 3108

Answer 2

The sum of adding all the possible three digit numbers formed by 7 , 2 , 5 using each of the digits only once is 3108

Given :

The numbers 7 , 2 , 5

To find :

The sum of adding all the possible three digit numbers formed by 7 , 2 , 5 using each of the digits only once

Solution :

Step 1 of 2 :

Write down all possible three digit numbers

Here the given numbers are 7 , 2 , 5

Since we can use each of the digits only once

So total number of possible three digit numbers

= 3!

= 6

All possible three digit numbers are 725 , 752 , 275 , 257 , 527 , 572

Step 2 of 2 :

Calculate the sum

The sum of adding all the possible three digit numbers formed by 7 , 2 , 5 using each of the digits only once

= 725 + 752 + 275 + 257 + 527 + 572

= 3108

Shortcut method :

The sum of adding all the possible three digit numbers formed by a , b , c using each of the digits only once is 222 × (a + b + c)

∴ The sum of adding all the possible three digit numbers formed by 7 , 2 , 5 using each of the digits only once

= 222 × (7 + 2 + 5)

= 222 × 14

= 3108

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