Question

what will be the work done by electric field in taking charge 3e from 10V to 25V​

Answer 1

${SOLUTION}$

Potential difference = 25 - 10 = 15V

Charge = 3C

Work = Charge × P.D

work = 15 × 3 = 45J

Hence,

Work Done = 45J

Answer 2

hey mate the work done here is 45 joule