What will be velocity of a satellite revolving around the earth at a height h above surface of earth of radius is R
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Assume the orbit to be circular. Takeradius of the earth as 6400 km and g at the surface of the earth to be 9.8 m/s2. ... Given: height of satellite above the surface of earth = h = 700 km, Radius of earth = R = 6400 km, G = 6.67 x 10-11 N m2/kg2 ; g = 9.8 m/s2.
pranavpawar775:
Ya but what further
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Explanation:
total energy of satellite in orbit =kE+(-PE)
KE=1/2mv2
PE= -GMm/(R+h)
1/2mv²=GMm/(R+h)
v²= gR²/(R+h)
v =R(g/R+h)½
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