Question

what will bets kinetic energy when its velocity is increas three times​

Answer 1

Original K.E =½mv²

New mass=m

New velocity=3v

So, new K.E=½m(3v)²

=½ m9v²

=9/2mv²

So,

$\frac{9mv ^{2} }{2} \times \frac{2}{mv ^{2} } \\ = 9$

So, the KE will be 9 times the original one.

Please mark as the brainliest.