What will happen if the KOH solution is removed from the conical flask containing germinating seeds in the experiment to show that Co_{2} is released during respiration ?
Answers
Answer:
This concept is from the chapter Life Processes of grade 10 biology (CBSE)
In case if the solution of KOH i.e. Potassium hydroxide is removed from the bell jar , no carbon dioxide will be absorbed by the KOH solution .
Thus , letting enough carbon dioxide to be present in the jar to allow photosynthesis normally by the plant .
All of this will lead to an end result that both the plants from jar A and jar B will show starch indicated by blue-black colour when tested with iodine .
Complete experiment explained :
Step 1 : Take 2 potted plants of same kind and almost same size . Leave them in sunlight for 3 to 4 hours so that they can complete photosynthesis and produce some amount of starch. Now check for starch with iodine solution. Both the leaves from both the plants will turn blue-black indicating that both are containing starch .
Step 2 : Take 2 bell jars and place either the plants completely or 1 leaf from each in them . In 1 of the bell jars place a watch-glass with KOH i.e. Potassium Hydroxide solution . This will absorb CO2 showing a difference in the end.
Step 3 : Seal the jars with vaseline to prevent any interference of atmospheric gases . Now , place both the jars in sunlight for 2 hours .
Step 4 : Take the leaves and test starch with iodine solution .
Observation :
Leaves from the jar containing KOH will not show blue-black colour which means they lack starch .
During photosynthesis every component is important . As KOH absorbed CO2 complete photosynthesis couldn't occur .
Hence , when absorbing component KOH is removed photosynthesis WILL occur .