Question

what would be the amount of acetic acid present in 1M solution if the stock solution is 0.2M solution of acetic acid?(11.55ml in 1000ml)

Answer 1

0.2M acetic acid contains 0.2 moles of acetic acid in 1L solution.
volume of 0.2 moles acetic acid = 11.55 ml
volume of 1 mole of acetic acid = $\frac{11.55}{0.2}= \frac{11.55 \times 10}{2} =57.75ml$

1M acetic acid contains 1 mole of acetic acid and its volume is 57.75ml.

Answer 2

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0.2M acetic acid contains 0.2 moles of acetic acid in 1L solution.

volume of 0.2 moles acetic acid = 11.55 ml

volume of 1 mole of acetic acid = $\frac{11.55}{0.2}= \frac{11.55 \times 10}{2} =57.75ml$

1M acetic acid contains 1 mole of acetic acid and its volume is 57.75ml.

HOPE SO IT WILL HELP.....