Question

what would be the early interest on RS 6000 at 10 p.c.p.a ?​

Answer 1

Given:

• Principal = Rs. 6000
• Time = 10 p.c.p.a

What To Find:

We have to find the early interest.

How To Find:

To find the early interest, we have to

• First, find the simple interest as early interest.
• Next, take a time period of 1 year as its default.
• Then, use the formula and get the interest.

Formula Needed:

$\bf SI = \dfrac{P \times R \times T}{100}$

Abbreviation Used In The Formula:

• SI = Simple Interest
• P = Principal
• R = Rate
• T = Time

Solution:

Using the formula,

$\sf \implies SI = \dfrac{P \times R \times T}{100}$

Substitute the values,

$\sf \implies SI = \dfrac{6000 \times 10 \times 1}{100}$

Cancel the zeros,

$\sf \implies SI = \dfrac{60 \!\!\!\not 0 \!\!\!\not 0 \times 10 \times 1}{1 \!\!\!\not 0 \!\!\!\not 0}$

Also written as,

$\sf \implies SI =60 \times 10 \times 1$

Multiply the numbers,

$\sf \implies SI = Rs. \: 600$

Final Answer:

The early interest or simple interest is Rs. 600.

Answer 2

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎‏‏‎ ‎$‏‏‎\mathtt{\bf{\small{\underline {\red{Required\: answer \: :- }}}}}$

‎⇨Given :-

• Principal =

• Time = 10 p.c.p.a

⇨To Find :-

Early Interest

⇨As We Know:-

$\boxed{ \purple{ \sf SI \: = \frac{P \times R \times T}{100} }} \:$

• P = principal
• SI = Simple Interest
• T = Time
• R = Rate

⇨Solution :-

$\underline{\frak{\dag \; using \; formula \: : - }}$

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎${ \purple{ \sf SI \: = \frac{P \times R \times T}{100} }} \:$

$\underline{\frak{\dag \; subsitute \; value: - }}$

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎$\begin{gathered}:\implies \sf si = \frac{6000 \times 10 \times 1}{100} \\\\\sf by \: cancelling \: zero\\\\:\implies \sf si = 60 \times 10 \times 1\\\\:\implies \sf multiply \: the \: numbers \\\\:\implies \underline{\boxed{\frak{\pink{ si \: = rs \: 600}}} }\; \bigstar\end{gathered}$

$\therefore \sf{\underline{hence \; simple \; interest \; is \; Rs \; 600 }}$

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