Question

what would be the interest for one year on rs. 8000 at rate 9 p.c.p.a?

please tell with method it's argent​

Answer 1

Answer:

P=8000

R=9 p.c.p.a

T=1 year

I=P×R×T÷100

I=8000×9×1÷100

HENCE, the interest for one year is 720 rupees.

Answer 2

Answer :-

• The compound interest for one year on Rs 8000 at the rate of 9 p.c.p.a is Rs 720.

To find :-

• The compound interest.

Step-by-step explanation :-

• Before finding the compound interest, let's find the amount!

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We know that :-

$\underline{\boxed{ \sf Amount = Principal \Bigg(1 + \dfrac{Rate}{100} \Bigg)^{Time}}}$

Here,

• Principal = Rs 8000.
• Rate = 9 percent compounded annually.
• Time = 1 year.

Hence,

$\rm Amount = 8000 \Bigg(1 + \dfrac{9}{100} \Bigg)^1$

Multiplying the fractions using their denominators,

$\rm Amount = 8000 \Bigg(\dfrac{1 \times 100 + 9 \times 1}{100}\Bigg) ^1$

On simplifying,

$\rm Amount = 8000 \Bigg(\dfrac{100 + 9}{100}\Bigg)^1$

Adding 9 to 100,

$\rm Amount = 8000 \Bigg(\dfrac{109}{100} \Bigg)^1$

Here, the power is 1, so it won't have any effect. Therefore removing the brackets,

$\rm Amount = 8000 \times \dfrac{109}{100}$

Cutting off the zeroes,

$\rm Amount = 80 \times \dfrac{109}{1}$

Now let's multiply the remaining numbers since we can't reduce them anymore.

$\rm Amount = 80 \times 109$

Multiplying 80 with 109,

$\overline{\boxed{\rm Amount = Rs \: 8720}}$

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• Now, as we know the amount, let's find the compound interest!

We know that :-

$\underline{\boxed{\sf CI = Amount - Principal}}$

Here,

• Amount = Rs 8720.
• Principal = Rs 8000.

Hence,

$\boxed{\tt CI = 8720 - 8000}$

$\overline{\boxed{\tt CI = Rs \: 720}}$

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Abbreviations used :-

CI = Compound Interest.