Question

What would be the osmotic pressure at 25°C of an aqueous solution containing 1.95g of sucrose present in 150 ml of solution?

Answer 1

Answer: The osmotic pressure at 25°C of an aqueous solution 0.9287 atm.

Explanation:

osmotic pressure =$\pi=\frac{nRT}{V}$

Given:

$n=\text{number of moles of sucrose}=\frac{\text{given mass  of sucrose}}{\text{molecular mass of sucrose}}=\frac{1.95}{342.29}$

Volume of the solution's=150 mL=$\frac{150}{1000} L$

R = universal gas constant = 0.08205 L atm/(mol K)

T = Temperature in Kelvins = $25^oC$=298 K($0^oC=273 K$)

$\pi=\frac{nRT}{V}=\frac{1.95\times 0.08205 L atm/(mol K)\times 298\times 1000}{342.29\times 150 L}= 0.9287 atm$

The osmotic pressure at 25°C of an aqueous solution 0.9287 atm.