What would be the ratio of mean square velocity of hydrogen gas at 50 kelvin and that of oxygen gas at 800 kelvin?
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ASKHome >> JEEMAIN and NEET >> Chemistry >> States of Matter: Liquids and Gases
what would be the ratio of mean square velocity of hydrogen gas at 50K and that of oxygen gas at 800K?
jeemain chemistry class12 states-of-matter kinetic-molecular-theory-of-gases mean-square-velocity easy
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asked Sep 18, 2014 by anonymous
edited Nov 7, 2014 by sharmaaparna1
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The average velocity of gas particles is found using the root mean square velocity formula which is =3RTM−−−−√=3RTM, where R is the Universal Gas Constant, T is the temperature in Kelvin and M is the mass in kg of a mole of gas.
Hence the Mass of H2H2 is 2 and that of O2O2 is 32 and the given temperature of H2H2 is 50 and that of O2O2 is 800 so for the given problem, the ratio of the velocities for H2:O2=502×32800−−−−−−−√H2:O2=502×32800=1
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ASKHome >> JEEMAIN and NEET >> Chemistry >> States of Matter: Liquids and Gases
what would be the ratio of mean square velocity of hydrogen gas at 50K and that of oxygen gas at 800K?
jeemain chemistry class12 states-of-matter kinetic-molecular-theory-of-gases mean-square-velocity easy
Share
asked Sep 18, 2014 by anonymous
edited Nov 7, 2014 by sharmaaparna1
1 Answer
Answer: 1
The average velocity of gas particles is found using the root mean square velocity formula which is =3RTM−−−−√=3RTM, where R is the Universal Gas Constant, T is the temperature in Kelvin and M is the mass in kg of a mole of gas.
Hence the Mass of H2H2 is 2 and that of O2O2 is 32 and the given temperature of H2H2 is 50 and that of O2O2 is 800 so for the given problem, the ratio of the velocities for H2:O2=502×32800−−−−−−−√H2:O2=502×32800=1
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