Question

When 10 ml of propane gas is combusted completely, volume of CO2 gas obtained in similar conditikn is-

Answer 1

Hello Dear.

Here is the answer---

Reaction of the Combustion of the Propane →

C₃H₈ + 5O₂  -------→ 3CO₂  + 4H₂O +HEAT.

Volume of the Propane = 10 ml.
= 0.01 litre.

Now, From the Equation,

1 mole of Propane Produces 3 mole of Carbon Dioxide.
∴ 22.4 litre of Propane Produces 3 × 22.4 liter of Carbon Dioxide.
∴ 1 liter of Propane Produces 3 liter of Carbon Dioxide.
∴ 0.01 liter of Propane Produces 3 × 0.01 liter of Carbon Dioxide.
    = 0.03 liter of Carbon Dioxide.
    = 30 ml of Carbon Dioxide.


∴ Volume of the Carbon Dioxide gas obtained by the combustion of 10 ml in a similar condition is 30 ml.


Hope it helps.

Answer 2

Chemical Equation:

C3H8 + 5O2 ----> 3CO2 +4H2O

According to equation:

1MOLE OF C3H8 produces 3 moles of CO2

As we know that 1 mole of any gas at STP occupies 22.4litres of gas.
so,

22.4litres of C3H8---> 3x22.4 litres of CO2

0.01 litres(10ml) ---->?

so, 0.01 litres of C3H8 gives=3×22.4*0.01/22.4
=3*0.01 litres
=0.03 litres of CO2
= 30ml of CO2 gas

Hence 10ml of propane on combustion produces 30ml of CO2 gas.