Chemistry, asked by gujaratinirmala, 10 months ago

when 20 ml of water is added to 80 ml of 5 M NaCl solution what is the molarity of resultant solution ​

Answers

Answered by darkbeauty
0

Answer:

20 molar.

Explanation:

M1V1=M2V2

given,M1=5M

V1= 80ml

V2= 20 ml

M2=400/20

=20 molar

Answered by kobenhavn
2

The molarity of resultant solution ​is 4M

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of acid which is stock NaCl

M_2\text{ and }V_2 are the molarity and volume of base which is diluted NaCl

We are given:

M_1=5M\\V_1=80mL\\M_2=?\\V_2=(80+20)mL=100ml

Putting values in above equation, we get:

5\times 80=M_2\times 100ml\\\\M_2=4M

Learn more about neutralization law

https://brainly.com/question/115806

https://brainly.com/question/3747208

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