When 44.8 litres of H2 is mixed with 22.4 litres of Cl2 each at STP, the moles of formed is equal to
Answers
Answered by
5
44.8 litres of H2 means 2 moles of H2.
22.4 litres of Cl2 means 1 mole of Cl2
so the reaction is,
2H2+Cl2=2HCl+H2
so, 1 mole of H2 and 2 moles of HCL are formed.
please mark as brainliest answer and follow
suhasarava3:
mark as brainliest answer
Answered by
0
Hey Dear,
◆ Answer -
2 mol HCl
● Explaintion -
No of moles of H2 -
n(H2) = 44.8 / 22.4
n(H2) = 2 mol
No of moles of Cl2 -
n(Cl2) = 22.4 / 22.4
n(Cl2) = 1 mol
Reaction of H2 & Cl2 takes place as -
H2 + Cl2 --> 2HCl
During the reaction 1 mol of H2 reacts with 1 mol of Cl2 to form 2 mol of Hcl. 1 mol of H2 remains unreacted.
Hope this helped you. Thanks for asking.
Similar questions