Question

when a 12 v battery is connected across an unknown resistor there is a current of 2.5 mA in the circuit. Find the value of resistance of the resistors

Answer 1

as we know, V=12V , I=2.5mA= 2.5*10^-3A

V=IR (OHM'S law)

R=V/I

R= 12/2.5*10^-3

R=4.8*10^3

Hence, resistance is 4.8*10^3

Answer 2

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According to Ohm’s law,

V = IR

=v/I

Here, V = 12 V and I = 2.5 mA = 0.0025 A Therefore,

=12/ 0.0025 = 4800 Ω = 4.8 kΩ

I hope, this will help you___❤❤

Thank you

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