Question

When a body slides down a smooth inclined plane the force acting on it parallel to the plane is root3 times the normal reaction. The slope of the plane is

Answer 1

$\tan( \alpha ) = slope = \frac{1}{ \sqrt{3} }$

Answer 2

Answer:

The slope is 30 degree

Explanation:

When the body goes down it makes an angle towards the direction. Then the below mentioned formula helps to find the angle:

$tan =\frac{N}{angle}$

Given: The body sliding to the plan with the angle of the $\sqrt{3}$

Find: Need to find the angle to slope.

Calculation:

Put the values in the above mentioned formula:

$tan =\frac{N}{angle}$

$tan =\frac{N}{N\sqrt{3} }\\tan =\frac{1}{\sqrt{3} }\\\\\\tan=30 degree$

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