Question

When a certain metal was irradiated with light of frequency 4.5*10^16 /s the photoelectrons emitted had three times the kinetic energy as the kinetic energy of photoelectrons emitted when the metal was irradited with light of frequency2.5*10^16 /s. Calculate the frequency of the metal.​

Answer 1

Explanation:

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Answer 2

Answer:

K.E = hv-hv0

KE/KE’=hv-hvo/hv’-hvo=v-vo/v’-vo’

KE/3KE=2.5*10^16-vo/4.5*10^16-vo

4.5*10^16-vo=7.5*10^16-3vo

Vo=1.5*10^16 Hz

Explanation:

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