Question

When a crown of mass 3kg is immersed in a water, then the apparent weight of it is 26N. Fing the density of the crown

Answer 1

Answer:

Apparent weight of iron = Weight of iron in air - weight of iron in water

As we know , Density =

volume

mass

So mass of iron piece in air = (volume) (density) =(10

−4

)(7800)kg=0.78kg

Weight of iron piece in air=mg=7.8N

weight of iron piece in water = upthrust = Vρg = 10

−4

(1000)10N=1N

so apparent weight of the iron piece =7.8N−1N=6.8N

so option (A) is correct

Answered By

toppr