When a pin of height 2cms is fixed at 10cms from a convex lens, the height of virtual image formed is 12cms .Find the focal length of the lens.
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Answer:
SORRY I DID NOT KNOW BIT STILL I WILL TRY.
Explanation:
h2h1=vu
∴12cm3cm=v−10cm ∴v=−40cm
Now 1f=1v−1u
∴1f=1−40cm=1−10cm=110cm−140cm
= 4−140cm=340cm
f=403cm=13.33 cm ( approximately) '
The focal length of the lens = 13.33 cm [ approximately].
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