Question

When a sound wave of frequency 300 Hz passes through a medium, the maximum displacement of a particle of the medium is 0.1 cm. The maximum velocity of the particle is equal to(a) 60π cms⁻¹(b) 30π cms⁻¹(c) 30 cms⁻¹(d) 60 cms⁻¹

Answer 1

$<b>$

Option B is Correct

Answer 2

Answer:

A) 60πcms⁻¹

Explanation:

Frequency of sound wave = 300Hz (Given)

Maximum displacement or amplitude of a particle of the medium = 0.1 cm (Given)

Maximum velocity = angular frequency × amplitude

Angular frequency = 2π × frequency

= 2π × 300 rad/s

= 600π rad/s

Maximum velocity of wave = 600π rad/s × 0.1cm

= 600π × 0.1

= 60πcms⁻¹

Thus, the maximum velocity of the particle is equal to 60πcms⁻¹