When a substance having mass 3 kg receives 600 cal of heat, its temperature increases by 10 °C. What is the specific heat of the substance?
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1002cal heat is required
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Answer:
Specific heat c = 2.95 j/kg k
Explanation:
Since we know that heat developed in the substance is directly proportional to
(1)mass of the substance.
(2)change in temperature of the substance due to which heat is developed
where is the sign of proportionality
where c = specific heat
m = 3 kg , Q = 600 x 4.184 joules = 2510.4 joules, \Delta T = 283 K
So,
So, specific heat c = 2.95 j/kg k
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