Question

When a substance having mass 3 kg receives 600 cal of heat, its temperature increases by 10 °C. What is the specific heat of the substance?

Answer 1

1002cal heat is required

Answer 2

Answer:

Specific heat c = 2.95 j/kg k

Explanation:

Since we know that heat developed in the substance is directly proportional to

(1)mass of the substance.

(2)change in temperature of the substance due to which heat is developed

$Q\ \alpha\ m\Delta T$

where $\alpha$ is the sign of proportionality

$Q = mc\Delta T$

where c = specific heat

m = 3 kg , Q = 600 x 4.184 joules = 2510.4 joules, \Delta T = 283 K

So, $c = \frac{Q}{m\Delta T}$

So, specific heat c = 2.95 j/kg k