When a substance having mass 3 kg receives 600 cal of heat, its temperature increases by 10 °C. What is the specific heat of the substance? please tell me it's steps
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Q=ms∆t
Q= 600 ,∆t=10,m=3
600=3×s×10
600/30=s
s=20
I think so my answer is correct.
Q= 600 ,∆t=10,m=3
600=3×s×10
600/30=s
s=20
I think so my answer is correct.
gellisurabhi:
is it correct
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