Question

when a two digit number is reversed,the new number is reduced by 63 and the sum of digits of these individual numbers is 9.Now,if these same number are converted into base 'x' the larger number becomes 5 times that of smaller one,then the value of 'x' is:

this question is belongs to digital number system

Answer 1

56, 65, 92 , 29 , 47, 74, 38 and 83

A simple trick to solve this :-

let the number be xy where x is the tens digit and y is the units digit.

So the number in relation would be written as

10x+y when this number is reversed it would become 10y+x

So adding these two numbers i.e. 10x + y + 10y + x = 11x + 11y

11(x+y)

so now we have to find the values of x and y which would sum up to 11.

So the answer of this question is 56, 65, 92 , 29 , 47, 74, 38 and 83