When an electron is accelerated
of x volts, its wavelength is
found to be 4.086A the value of x
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Given:
- The wavelength of the electron (λ) = 4.086 A⁰ = 4.086*10⁻¹⁰ m
- The charge possessed by an electron (e) = 1.6*10⁻¹⁹ C
- The value of Planck's constant = 6.62*10⁻³⁴ Js
- The speed of light (c) = 3*10⁸ m/s
To find:
The value of the potential (x) through which the electron has been accelerated.
Solution:
- According to conservation of energy, e*x = h*c/λ ⇒ x = (h*c)/(λ*e) = 3.03*10³ V
Answer:
The value of the potential through which the electron has been accelerated is equal to 3.03*10³ V
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