Question

When an excited hydrogen atom emits a photon of energy 10.2 ev, the change in angular momentum according to bohr's model is?

Answer 1

Answer:

Q:When an excited hydrogen atom emits a photon of energy 10.2 ev, the change in angular momentum according to bohr's model is?

Explanation:

For energy of proton 10.2 ev transition will be from n = 2 to n = 1

we know angular momentum of e` = nh/2n`

change = h/2n` (1-2)

= -h/2n`

Answer 2

There is a change of h/2π in angular momentum when an excited hydrogen atom emits a photon of energy 10.2eV:

• Neils Bohr gave Bohr's theory for hydrogen and hydrogen-like atoms explaining the general features of their structure and spectrum.
• According to Bohr's theory, the angular momentum of Hydrogen and Hydrogen like species in a given stationary state could be obtained by the following equation:

                                     L = n.$\frac{h}{2\pi }$                    

Where,

L = angular momentum

n = 1,2,3...

• This implies that angular momentum is present as multiples of h/2π
• For the emission of 10.2eV of energy, the electron transits from the  n=2 level to the n=1 level.

                                       L = n.h/2π    

                                       L = (2-1).h/2π  = h/2π

Thus, there is a change of h/2π in angular momentum when an excited hydrogen atom emits a photon of energy 10.2eV.