Math, asked by manishjha13cool, 10 months ago

when an interger
is added to itself is the sum always greater than the integers discuss for positive interger , negative integers and zero​

Answers

Answered by Anonymous
5

Answer:

1.

Step-by-step explanation:

x+x=2x

Now case I if x > 0 say x=0+k( k any positive number)

2x=0+2k

as 2k>0 then

2x>x

Sum is greater than the number

========================================

Case II x<0 let x=0-k   ( k any positive number)

2x=0-2k

as -2k < -k

Hence 2x < x

Sum is is less then number

===============================================

case II

If x=0

then 2x=0

so no change

Answered by sahpoonam800gmailcom
3

Step-by-step explanation:

FOR POSITIVE INTEGERS :

for positive integers the sum will always be greater than the integer.

example:

  • first no. - 2

second no.- 2

sum= 2+2= 4

  • first no.-3

second no.-3

sum = 3+3 = 6

Hence, in both the examples the sum is greater then the integer.

FOR NEGATIVE INTEGER :

for negative integer the no.will be smaller then the integer.

Examples:

  • first no. : -2
  • second no. : -2

sum: -2 + ( -2)= -4

FOR ZERO :

for zero sum will always remain zero.

Examples:

0+0= 0

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