Question

when an object of weight w in air is immense in a liquid its weight in the liquid is found to be W1 when it is immersed in water the weight of water displaced is found to be W2 . the relative density of liquid is
A.W2/W1
B.W-W1/W2
C.W2/W-W1
D.W-W2/W1
JALDI BATO BHAILOG​

Answer 1

W-W2 /W1 I think may be it help you

Answer 2

Relative ensity is defined as Density of liquid / density of water

When object is placed in liquid,

apparent weight = actual weight of an object - buoyant force

W1 = W - v*g*sigma

Where, sigma is the density of water

sigma = W1-W/vg

Therefore,

relative density = sigma / p = [(W1-W)/vg] / [(W1-W)/vg]

and W2 = pvg

relative density = (W1-W)/W2