Question

when calcium carbonate is strongly heated 28g of calcium oxide is obtain . calculate the volume of co2 liberated at STP​

Answer 1

Answer:

Explanation:

CaCO3—>CaO+CO2

Mass of CaO=28

Moles=Mass/GMM

=28/56

=1/2

1 mole of CaO=1 mole of CO2

1/2 mole of CaO=1/2 mole of CO2

Moles=Volume/22.4

1/2 =Volume/22.4

1/2*22.4=VOLUME

11.2L is volume of of CO2

Hope it helps