Question

when each sides of a square is reduced by 2cm the area becomes 64cm find the sides of Original square​

Answer 1

Answer:

Hi ,

Let side of the square = a m

If one side of a square is increased by 2 m

and other side is reduced by 2 m , a rectangle

is formed

Dimensions of the rectangle

length = ( a + 2 ) m

Breadth = ( a - 2 ) m

According to the problem given ,

Perimeter of the rectangle = 48 m

2( l + b ) = 48

2 [ a + 2 + a - 2 ] = 48

2 × 2a = 48

4a = 48

a = 48 / 4

a = 12

Therefore side of the original

square = a = 12m

I hope this helps you.

:)

Step-by-step explanation:

Answer 2

Answer:

10 cm

Step-by-step explanation:

let the original side of square is x cm

so according to question,

(x-2)^2=64

x-2=√64=8

x=10cm