When ethyl alcohol and acetic acid mixed together in equality positions equilibrium is?
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According to the definition, "Equilibrium constant (Kc) is the ratio of the products of the product concentration that is raised to the powers of their coefficient to the products of the reactant concentration that is raised to powers of their coefficient."
The reaction equation will be -
C₂H₅OH + CH₃COOH → CH₃COOC₂H₅ + H₂O
In this equation, the coefficients are all 1 and so, the exponents are disregarded. Also, in this esterification reaction, 1 mole of water is produced for every mole of ethyl acetate produced.
Kc = frac of {[H₂O] x [CH₃COOC₂H₅]} {[CH₃COOH] x [C₂H₅OH]}
Kc = ((2/3) x (2/3)/1 = (4/9)
Therefore, Kc = 0.44.
The reaction equation will be -
C₂H₅OH + CH₃COOH → CH₃COOC₂H₅ + H₂O
In this equation, the coefficients are all 1 and so, the exponents are disregarded. Also, in this esterification reaction, 1 mole of water is produced for every mole of ethyl acetate produced.
Kc = frac of {[H₂O] x [CH₃COOC₂H₅]} {[CH₃COOH] x [C₂H₅OH]}
Kc = ((2/3) x (2/3)/1 = (4/9)
Therefore, Kc = 0.44.
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Explanation:
When ethanol and acetic acid are mixed together in equimolar proportions, equilibrium is attained when 2/3rd of acid and alcohol are consumed.
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