when four equal resistor are connected in series with a battery they dissipate power of 10watt. the power dissipated through any of them if connected across the same battery will be plz reply fast.............
Answers
Answer:160 W
Explanation:
The power that a battery “dissipates” is virtually never the same as the power the battery delivers to its load. The power that a battery delivers to a load is equal to the product of the square of the load current, and the load resistance. In contrast, the power that a battery dissipates, is equal to the product of the square of the load current, and the internal resistance of the battery.
Thus the power that the battery delivers to a load resistance, obviously depends on that load resistance, which is of course dependent on how the resistors that comprise that load resistance, are connected.
For 4 u identical resistors of value R connected in series, the equivalent total resistance Rt = 4R. For four identical resistances of value R connected in parallel, the equivalent total resistance is Rr = R/4. Thus the total resistance of the series connection is 4R/(R/4) =16 times the resistance of the parallel connection, and (assuming the battery is able to supply the required current), the source current (s supplied to the parallel-connected load, will be 16 times the currrent supplied to the series-connected load. However, since the power supplied to the load varies with the square of the source current Is, then the power supplied to the parallel-connected load, will be (16^2)/16 = 16 times the power supplied to (and dissipated by) the series-connected load. That is, 16 x 10 = 160W.