When p(x) is divides by ax-b
then the remainder is
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Answered by
1
Answer:
0
Step-by-step explanation:
since p(x) divides ax-b
p(x)=ax-b----1
x=b/a----2
sub 2 in 1
a(b/a)-b=0
hope it helps!!
Answered by
3
Answer:
By Remainder theorem :
If p(x) is divided by ( ax - b ) then the remainder is p ( b/a ) .
it is easy to find the zero of p( x ) . which is given below ,
ax - b = 0
ax = b
x = - b/a
remainder is p( -b/a )
Hope it is helpful.
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