when
point charge of 6ue is moved
between two points of electric field,the work
done is 1.8*1/10000. The potential
difference between two point is
a) 1. 08V
b) 1.08v
d) 30v
C) 3 v
Answers
Answered by
0
Answer:
we know:
∆V= Work done ( by external agent)/q
so:
∆V= 1.8x10^-5 /6 .
= 3 × 10^-6 J/c.
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Explanation:
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